help on geometric probability distribution problem?
experience has a chance "p" for success. a person repeats experience up
until He got a success after second time. what is the chance that He
achieves second success in the 6th experience?
correct answer: 5p^2(1-p)^4
My approach was to identify that this problem is a geometric distribution
since the number of cycles to success is known. So if a person had a
success after second experience the Geo(p) would be (1-p)p now we want to
know what is the chance of a second success on sixth experience so I
thought it would be "(1-p)*p+(1-p)^5*p" which is wrong .
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